from urllib.parse import urlparse
import os

url = "https://sns-video-hw.xhscdn.com/stream/110/258/01e6cd08be6e36ad010370019190eceaac_258.mp4"

# 解析URL
parsed_url = urlparse(url)
# 获取路径部分
path = parsed_url.path
# 从路径中提取文件名
filename = os.path.basename(path)

print(f"完整路径: {path}")
print(f"文件名: {filename}")