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优化案件模块

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This commit is contained in:
27942
2026-01-20 17:58:42 +08:00
parent 9e8f7f08ed
commit f3911fe36f
1 changed files with 42 additions and 20 deletions
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62
finance/views.py
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@@ -1796,10 +1796,12 @@ class loandisplay(APIView):
except EmptyPage:
user_agents_page = paginator.page(paginator.num_pages)
data = []
import re
from business.models import Case, ProjectRegistration
for info in user_agents_page.object_list:
# 通过合同号查找关联的案件，提取客户名字
# 通过合同号查找关联的案件，提取客户名字（只返回纯名字）
customer_names = []
from business.models import Case, ProjectRegistration
if info.ContractNo:
# 优先从Case（案件管理）中查找
@@ -1809,27 +1811,39 @@ class loandisplay(APIView):
is_deleted=False
).first()
if case:
# 提取委托人名字
# 提取委托人名字（只返回纯名字）
if case.client_name:
# 提取名字部分（去除身份证号等信息）
# 提取名字部分：去除身份证号、括号内容等
client_name = case.client_name.split('，')[0].split(',')[0].strip()
if client_name:
client_name = re.sub(r'[（(].*?[）)]', '', client_name) # 去除括号内容
client_name = re.sub(r'\d{15,18}', '', client_name) # 去除身份证号
client_name = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', client_name).strip() # 只保留中文、英文、数字
if client_name and len(client_name) >= 2:
customer_names.append(client_name)
# 提取相对方名字
# 提取相对方名字（只返回纯名字）
if case.party_name:
party_name = case.party_name.split('，')[0].split(',')[0].strip()
if party_name:
party_name = re.sub(r'[（(].*?[）)]', '', party_name) # 去除括号内容
party_name = re.sub(r'\d{15,18}', '', party_name) # 去除身份证号
party_name = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', party_name).strip() # 只保留中文、英文、数字
if party_name and len(party_name) >= 2:
customer_names.append(party_name)
# 如果Case中没有，从关联的project获取
if not customer_names and case.project:
if case.project.client_info:
client_info = case.project.client_info.split('，')[0].split(',')[0].strip()
if client_info:
client_info = re.sub(r'[（(].*?[）)]', '', client_info) # 去除括号内容
client_info = re.sub(r'\d{15,18}', '', client_info) # 去除身份证号
client_info = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', client_info).strip() # 只保留中文、英文、数字
if client_info and len(client_info) >= 2:
customer_names.append(client_info)
if case.project.party_info:
party_info = case.project.party_info.split('，')[0].split(',')[0].strip()
if party_info:
party_info = re.sub(r'[（(].*?[）)]', '', party_info) # 去除括号内容
party_info = re.sub(r'\d{15,18}', '', party_info) # 去除身份证号
party_info = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', party_info).strip() # 只保留中文、英文、数字
if party_info and len(party_info) >= 2:
customer_names.append(party_info)
except:
pass
@@ -1842,15 +1856,21 @@ class loandisplay(APIView):
is_deleted=False
).first()
if project:
# 提取委托人名字
# 提取委托人名字（只返回纯名字）
if project.client_info:
client_info = project.client_info.split('，')[0].split(',')[0].strip()
if client_info:
client_info = re.sub(r'[（(].*?[）)]', '', client_info) # 去除括号内容
client_info = re.sub(r'\d{15,18}', '', client_info) # 去除身份证号
client_info = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', client_info).strip() # 只保留中文、英文、数字
if client_info and len(client_info) >= 2:
customer_names.append(client_info)
# 提取相对方名字
# 提取相对方名字（只返回纯名字）
if project.party_info:
party_info = project.party_info.split('，')[0].split(',')[0].strip()
if party_info:
party_info = re.sub(r'[（(].*?[）)]', '', party_info) # 去除括号内容
party_info = re.sub(r'\d{15,18}', '', party_info) # 去除身份证号
party_info = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', party_info).strip() # 只保留中文、英文、数字
if party_info and len(party_info) >= 2:
customer_names.append(party_info)
except:
pass
@@ -1860,21 +1880,23 @@ class loandisplay(APIView):
# 尝试从CustomerID中提取名字（可能包含多个客户，用逗号或分号分隔）
customer_id_str = str(info.CustomerID).strip()
if customer_id_str:
# 尝试按逗号、分号、空格等分隔
import re
# 先尝试按常见分隔符分割
parts = re.split(r'[,，;；\s]+', customer_id_str)
for part in parts:
part = part.strip()
if part:
# 提取名字部分（去除身份证号等信息）
name = part.split('，')[0].split(',')[0].split('（')[0].split('(')[0].strip()
if name and name not in customer_names:
# 提取纯名字部分：去除身份证号、括号内容、特殊字符等
# 只保留中文字符、英文字母、数字（用于名字）
name = re.sub(r'[（(].*?[）)]', '', part) # 去除括号内容
name = re.sub(r'\d{15,18}', '', name) # 去除身份证号
name = re.sub(r'[^\u4e00-\u9fa5a-zA-Z0-9]', '', name) # 只保留中文、英文、数字
name = name.strip()
if name and len(name) >= 2 and name not in customer_names: # 名字至少2个字符
customer_names.append(name)
# 去重并连接
# 去重并连接，只返回客户名字
customer_names = list(dict.fromkeys(customer_names)) # 保持顺序去重
customer_name_str = '，'.join(customer_names) if customer_names else (info.CustomerID or '')
customer_name_str = '，'.join(customer_names) if customer_names else ''
itme = {
'id': info.id,